小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com2023-2024学年下学期期末模拟考试(安徽专用)七年级数学一、选择题(本大题共10小题,每小题4分,共40分.在每小题给出的四个选项中,只有一个选项是符合题目要求的)12345678910ACCADADCCD二、填空题(本大题共4小题,每小题4分,共16分)11.12.13.14.三、(本大题共2小题,每小题5分,满分10分)15.【答案】(1)0(2)或【分析】本题主要考查了实数的运算,求平方根的方法解方程:(1)先计算算术平方根和立方根,再计算加减法即可;(2)根据求平方根的方法解方程即可.【详解】(1)解:;··············································2分(2)解: ,∴,∴或,∴或.·············································5分16.【答案】,整数解为,,0,1【分析】本题主要考查了解一元一次不等组,不等式组的整数解,解题的关键是熟练掌握解不等式组的基本步骤,能根据不等式的解集得出不等式组的解集.先分别求出两个不等式的解集,再求出不等式组的解集,最后求出整数解,即可解答.小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com【详解】解:解不等式①,得,·············································1分解不等式②,得·············································2分∴原不等式组的解集为·············································4分∴原不等式组的整数解为,,0,1.·············································5分四、(本大题共2小题,每小题6分,满分12分)17.【答案】令,结果为6【分析】根据分式的运算法则化简,取合适的字母值代入计算;【详解】解:·············································4分令,原式.·············································6分【点睛】本题考查分式的化简求值,掌握分式的运算法则是解题的关键.18.【答案】(1),,(2)见解析(3)【分析】本题考查了作图﹣平移变换,作图时要先找到图形的关键点,分别把这几个关键点按照平移的方向和距离确定对应点后,再顺次连接对应点即可得到平移后的图形.(1)根据点的坐标表示方法写出点,,的坐标;(2)根据(1)描点连线即可;(3)根据点的坐标平移方法即可求解.【详解】(1),,;·············································3分(2)如图,三角形即为所作;小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com·············································4分(3)由题意可知,故答案为:.·············································6分五、(本大题共2小题,每小题8分,满分16分)19.【答案】(1),见解析(2)【分析】此题考查了平行线的性质和判定定理,熟练掌握各定理是解题的关键:(1)由推出,得到,进而推出;(2)根据角平分线的性质得到,及,求出,再利用平行线的性质求出的度数.【详解】(1),理由如下: ,∴,即, ,∴,∴·············································3分(2) 平分,,∴,·············································5分∴,∴·············································6分 ,小学、初中、高中各种试卷真题知识归纳文案合同PPT等免费下载www.doc985.com∴,∴··············...